36(5-x^2)=0

Solution for 36(5-x^2)=0 equation:

36(5-x^2)=0

We multiply parentheses

-36x^2+180=0

a = -36; b = 0; c = +180;
Δ = b2-4ac
Δ = 02-4·(-36)·180
Δ = 25920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25920}=\sqrt{5184*5}=\sqrt{5184}*\sqrt{5}=72\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72\sqrt{5}}{2*-36}=\frac{0-72\sqrt{5}}{-72}
=-\frac{72\sqrt{5}}{-72}
=-\frac{\sqrt{5}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72\sqrt{5}}{2*-36}=\frac{0+72\sqrt{5}}{-72}
=\frac{72\sqrt{5}}{-72}
=\frac{\sqrt{5}}{-1}
$